21 янв 2018
50) 1 , 8 , 22 , 43, sonlar ketma ketligi shunday xususiyatga egaki, ikkita quwni hadlarining ayirmasi 7, 14, 21, ...
Arifmetik progressiya ni tawkil etadi. Berilgan ketma ketlikning nechanchi hadi 35351 ga teng buladi ?
25) Arifmetik progressiya ning hadlari 19 ta . uning urta hadi 21 ga teng. Wu progressiyaning hadlari yigindisini toping.
34) Dastlabki 4 ta hadi yigindisi 124 ga, oxirgi turttasiniki 156 ga teng. Wu arifmetik Progressiya ning hadlari yigindisi 350 ga teng . Progressiyaning nechta hadi bor ?
38) Arifmetik progressiya ning dastlabki nechta hadini olmaylik ularning yigindisi hadlar soni kvadratining uchlanganiga teng. Wu progressiyaning yettinchi hadini toping.
25) Arifmetik progressiya ning hadlari 19 ta . uning urta hadi 21 ga teng. Wu progressiyaning hadlari yigindisini toping.
34) Dastlabki 4 ta hadi yigindisi 124 ga, oxirgi turttasiniki 156 ga teng. Wu arifmetik Progressiya ning hadlari yigindisi 350 ga teng . Progressiyaning nechta hadi bor ?
38) Arifmetik progressiya ning dastlabki nechta hadini olmaylik ularning yigindisi hadlar soni kvadratining uchlanganiga teng. Wu progressiyaning yettinchi hadini toping.
35) natural sonlar qatori har biri natural sonning kvadrati b.n tugaydigan quyidagi qismlarga ajratilgan :
1 , (2, 3, 4) , ( 5, 6, 7, 8, 9) , (10, 11, 12, 13, 14, 15, 16) , ....
10-qismdagi sonla yigindisini toping.
a1*a3=528
a1=?
124 ga, oxirgi turttasiniki 156
ga teng. Wu arifmetik
Progressiya ning hadlari
yigindisi 350 ga teng .
Progressiyaning nechta hadi
bor ?
A1+a4=62